Java Array Majority Element

This post was originally published on Java Code Geeks

In Java, determining the majority element of an array involves identifying the element that appears more than half of the array’s size. Let us delve into understanding how to use Java array to find the majority element efficiently.

1. Using a Sorting Approach to Find the Majority Element of an Array in Java

In Java, you can find the majority element of an array efficiently using a sorting approach. Let’s break down the code step by step:

package com.jcg.example; import java.util.Arrays; public class MajorityElementFinder { public static int findMajorityElement(int[] nums) { Arrays.sort(nums); int candidate = nums[nums.length / 2]; int count = 0; for (int num : nums) { if (num == candidate) { count++; } } if (count > nums.length / 2) { return candidate; // Majority element found } else { return -1; // No majority element } } public static void main(String[] args) { int[] nums = {3, 3, 4, 2, 4, 4, 2, 4, 4}; // int[] nums = {3, 3, 4, 4, 5, 5, 2, 2, 1}; int majorityElement = findMajorityElement(nums); if (majorityElement != -1) { System.out.println(“Majority Element: ” + majorityElement); } else { System.out.println(“No Majority Element found.”); } } } 1.1 Code Explanation and Output

The code defines

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